-3x(4x=3)-43=-4(6x+1)

Solution for -3x(4x=3)-43=-4(6x+1) equation:

-3x(4x=3)-43=-4(6x+1)

We move all terms to the left:

-3x(4x-(3)-43)=0

We add all the numbers together, and all the variables

-3x(4x-46)=0

We multiply parentheses

-12x^2+138x=0

a = -12; b = 138; c = 0;
Δ = b2-4ac
Δ = 1382-4·(-12)·0
Δ = 19044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19044}=138$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(138)-138}{2*-12}=\frac{-276}{-24}
=11+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(138)+138}{2*-12}=\frac{0}{-24}
=0
$