12(3x-2)-5(4+1)=3(4-4x)

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Solution for 12(3x-2)-5(4+1)=3(4-4x) equation: 



12(3x-2)-5(4+1)=3(4-4x)

We move all terms to the left:

12(3x-2)-5(4+1)-(3(4-4x))=0

We add all the numbers together, and all the variables

12(3x-2)-(3(-4x+4))-55=0

We multiply parentheses

36x-(3(-4x+4))-24-55=0



We calculate terms in parentheses: -(3(-4x+4)), so:

3(-4x+4)

We multiply parentheses

-12x+12

Back to the equation:

-(-12x+12)



We add all the numbers together, and all the variables

36x-(-12x+12)-79=0

We get rid of parentheses

36x+12x-12-79=0

We add all the numbers together, and all the variables

48x-91=0

We move all terms containing x to the left, all other terms to the right

48x=91

x=91/48

x=1+43/48

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