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-3x(2x-5)+3x+12=63
We move all terms to the left:
-3x(2x-5)+3x+12-(63)=0
We add all the numbers together, and all the variables
3x-3x(2x-5)-51=0
We multiply parentheses
-6x^2+3x+15x-51=0
We add all the numbers together, and all the variables
-6x^2+18x-51=0
a = -6; b = 18; c = -51;
Δ = b2-4ac
Δ = 182-4·(-6)·(-51)
Δ = -900
Delta is less than zero, so there is no solution for the equation
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