-3x(2+3x)-x=-26

Solution for -3x(2+3x)-x=-26 equation:

-3x(2+3x)-x=-26

We move all terms to the left:

-3x(2+3x)-x-(-26)=0

We add all the numbers together, and all the variables

-3x(3x+2)-x-(-26)=0

We add all the numbers together, and all the variables

-1x-3x(3x+2)+26=0

We multiply parentheses

-9x^2-1x-6x+26=0

We add all the numbers together, and all the variables

-9x^2-7x+26=0

a = -9; b = -7; c = +26;
Δ = b2-4ac
Δ = -72-4·(-9)·26
Δ = 985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{985}}{2*-9}=\frac{7-\sqrt{985}}{-18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{985}}{2*-9}=\frac{7+\sqrt{985}}{-18}
$