20=3+5(d+9)

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Solution for 20=3+5(d+9) equation: 



20=3+5(d+9)

We move all terms to the left:

20-(3+5(d+9))=0



We calculate terms in parentheses: -(3+5(d+9)), so:

3+5(d+9)

determiningTheFunctionDomain
5(d+9)+3

We multiply parentheses

5d+45+3

We add all the numbers together, and all the variables

5d+48

Back to the equation:

-(5d+48)



We get rid of parentheses

-5d-48+20=0

We add all the numbers together, and all the variables

-5d-28=0

We move all terms containing d to the left, all other terms to the right

-5d=28

d=28/-5

d=-5+3/5

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