-3r+3(-6r-5)=-7(r-2)

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Solution for -3r+3(-6r-5)=-7(r-2) equation:



-3r+3(-6r-5)=-7(r-2)
We move all terms to the left:
-3r+3(-6r-5)-(-7(r-2))=0
We multiply parentheses
-3r-18r-(-7(r-2))-15=0
We calculate terms in parentheses: -(-7(r-2)), so:
-7(r-2)
We multiply parentheses
-7r+14
Back to the equation:
-(-7r+14)
We add all the numbers together, and all the variables
-21r-(-7r+14)-15=0
We get rid of parentheses
-21r+7r-14-15=0
We add all the numbers together, and all the variables
-14r-29=0
We move all terms containing r to the left, all other terms to the right
-14r=29
r=29/-14
r=-2+1/14

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