3(-4c-4)=2(10-4c)

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Solution for 3(-4c-4)=2(10-4c) equation: 



3(-4c-4)=2(10-4c)

We move all terms to the left:

3(-4c-4)-(2(10-4c))=0

We add all the numbers together, and all the variables

3(-4c-4)-(2(-4c+10))=0

We multiply parentheses

-12c-(2(-4c+10))-12=0



We calculate terms in parentheses: -(2(-4c+10)), so:

2(-4c+10)

We multiply parentheses

-8c+20

Back to the equation:

-(-8c+20)



We get rid of parentheses

-12c+8c-20-12=0

We add all the numbers together, and all the variables

-4c-32=0

We move all terms containing c to the left, all other terms to the right

-4c=32

c=32/-4

c=-8

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