-3n(1+n)-2n=-6(n-2)

Solution for -3n(1+n)-2n=-6(n-2) equation:

-3n(1+n)-2n=-6(n-2)

We move all terms to the left:

-3n(1+n)-2n-(-6(n-2))=0

We add all the numbers together, and all the variables

-3n(n+1)-2n-(-6(n-2))=0

We add all the numbers together, and all the variables

-2n-3n(n+1)-(-6(n-2))=0

We multiply parentheses

-3n^2-2n-3n-(-6(n-2))=0


We calculate terms in parentheses: -(-6(n-2)), so:

-6(n-2)

We multiply parentheses

-6n+12

Back to the equation:

-(-6n+12)


We add all the numbers together, and all the variables

-3n^2-5n-(-6n+12)=0

We get rid of parentheses

-3n^2-5n+6n-12=0

We add all the numbers together, and all the variables

-3n^2+n-12=0

a = -3; b = 1; c = -12;
Δ = b2-4ac
Δ = 12-4·(-3)·(-12)
Δ = -143
Delta is less than zero, so there is no solution for the equation