-6=2(f-13)+-6

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Solution for -6=2(f-13)+-6 equation: 



-6=2(f-13)+-6

We move all terms to the left:

-6-(2(f-13)+-6)=0

We use the square of the difference formula

-(2(f-13)-6)-6=0



We calculate terms in parentheses: -(2(f-13)-6), so:

2(f-13)-6

We multiply parentheses

2f-26-6

We add all the numbers together, and all the variables

2f-32

Back to the equation:

-(2f-32)



We get rid of parentheses

-2f+32-6=0

We add all the numbers together, and all the variables

-2f+26=0

We move all terms containing f to the left, all other terms to the right

-2f=-26

f=-26/-2

f=+13

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