-3=(2/5*2)+c

Solution for -3=(2/5*2)+c equation:

-3=(2/5*2)+c

We move all terms to the left:

-3-((2/5*2)+c)=0


Domain of the equation: 5*2)+c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

-((+2/5*2)+c)-3=0

We multiply all the terms by the denominator


-((+2-3*5*2)+c)=0


We calculate terms in parentheses: -((+2-3*5*2)+c), so:

(+2-3*5*2)+c

determiningTheFunctionDomain
c+(+2-3*5*2)

We add all the numbers together, and all the variables

c+(-28)

We add all the numbers together, and all the variables

c-28

Back to the equation:

-(c-28)


We get rid of parentheses

-c+28=0

We add all the numbers together, and all the variables

-1c+28=0

We move all terms containing c to the left, all other terms to the right

-c=-28

c=-28/-1

c=+28