.40c+(.50)(500-c)=210

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Solution for .40c+(.50)(500-c)=210 equation: 



.40c+(.50)(500-c)=210

We move all terms to the left:

.40c+(.50)(500-c)-(210)=0

We add all the numbers together, and all the variables

.40c+(0.5)(-1c+500)-210=0

We multiply parentheses ..

.40c+(-0.5c+250)-210=0

We get rid of parentheses

.40c-0.5c+250-210=0

We add all the numbers together, and all the variables

-0.1c+40=0

We move all terms containing c to the left, all other terms to the right

-0.1c=-40

c=-40/-0.1

c=+400

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