-38x2+68x=0

Solution for -38x2+68x=0 equation:

-38x^2+68x=0

a = -38; b = 68; c = 0;
Δ = b2-4ac
Δ = 682-4·(-38)·0
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-68}{2*-38}=\frac{-136}{-76}
=1+15/19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+68}{2*-38}=\frac{0}{-76}
=0
$