-38+16c=8(2c-6)+10

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Solution for -38+16c=8(2c-6)+10 equation: 



-38+16c=8(2c-6)+10

We move all terms to the left:

-38+16c-(8(2c-6)+10)=0



We calculate terms in parentheses: -(8(2c-6)+10), so:

8(2c-6)+10

We multiply parentheses

16c-48+10

We add all the numbers together, and all the variables

16c-38

Back to the equation:

-(16c-38)



We get rid of parentheses

16c-16c+38-38=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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