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-7.x+15x^2-4=0
We add all the numbers together, and all the variables
15x^2-7x-4=0
a = 15; b = -7; c = -4;
Δ = b2-4ac
Δ = -72-4·15·(-4)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-17}{2*15}=\frac{-10}{30} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+17}{2*15}=\frac{24}{30} =4/5 $
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