-36=2(y-3)+8y

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Solution for -36=2(y-3)+8y equation: 



-36=2(y-3)+8y

We move all terms to the left:

-36-(2(y-3)+8y)=0



We calculate terms in parentheses: -(2(y-3)+8y), so:

2(y-3)+8y

We add all the numbers together, and all the variables

8y+2(y-3)

We multiply parentheses

8y+2y-6

We add all the numbers together, and all the variables

10y-6

Back to the equation:

-(10y-6)



We get rid of parentheses

-10y+6-36=0

We add all the numbers together, and all the variables

-10y-30=0

We move all terms containing y to the left, all other terms to the right

-10y=30

y=30/-10

y=-3

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