2(15c+8)=9(2c+4)-(3c+2)

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Solution for 2(15c+8)=9(2c+4)-(3c+2) equation: 



2(15c+8)=9(2c+4)-(3c+2)

We move all terms to the left:

2(15c+8)-(9(2c+4)-(3c+2))=0

We multiply parentheses

30c-(9(2c+4)-(3c+2))+16=0



We calculate terms in parentheses: -(9(2c+4)-(3c+2)), so:

9(2c+4)-(3c+2)

We multiply parentheses

18c-(3c+2)+36

We get rid of parentheses

18c-3c-2+36

We add all the numbers together, and all the variables

15c+34

Back to the equation:

-(15c+34)



We get rid of parentheses

30c-15c-34+16=0

We add all the numbers together, and all the variables

15c-18=0

We move all terms containing c to the left, all other terms to the right

15c=18

c=18/15

c=1+1/5

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