-32+7z=3(2z+7)

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Solution for -32+7z=3(2z+7) equation: 



-32+7z=3(2z+7)

We move all terms to the left:

-32+7z-(3(2z+7))=0



We calculate terms in parentheses: -(3(2z+7)), so:

3(2z+7)

We multiply parentheses

6z+21

Back to the equation:

-(6z+21)



We get rid of parentheses

7z-6z-21-32=0

We add all the numbers together, and all the variables

z-53=0

We move all terms containing z to the left, all other terms to the right

z=53

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