6(3-n)+4=1-(n-3)

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Solution for 6(3-n)+4=1-(n-3) equation: 



6(3-n)+4=1-(n-3)

We move all terms to the left:

6(3-n)+4-(1-(n-3))=0

We add all the numbers together, and all the variables

6(-1n+3)-(1-(n-3))+4=0

We multiply parentheses

-6n-(1-(n-3))+18+4=0



We calculate terms in parentheses: -(1-(n-3)), so:

1-(n-3)

determiningTheFunctionDomain
-(n-3)+1

We get rid of parentheses

-n+3+1

We add all the numbers together, and all the variables

-1n+4

Back to the equation:

-(-1n+4)



We add all the numbers together, and all the variables

-6n-(-1n+4)+22=0

We get rid of parentheses

-6n+1n-4+22=0

We add all the numbers together, and all the variables

-5n+18=0

We move all terms containing n to the left, all other terms to the right

-5n=-18

n=-18/-5

n=3+3/5

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