-31=3(-x-3)+4(1+4x)

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Solution for -31=3(-x-3)+4(1+4x) equation: 



-31=3(-x-3)+4(1+4x)

We move all terms to the left:

-31-(3(-x-3)+4(1+4x))=0

We add all the numbers together, and all the variables

-(3(-1x-3)+4(4x+1))-31=0



We calculate terms in parentheses: -(3(-1x-3)+4(4x+1)), so:

3(-1x-3)+4(4x+1)

We multiply parentheses

-3x+16x-9+4

We add all the numbers together, and all the variables

13x-5

Back to the equation:

-(13x-5)



We get rid of parentheses

-13x+5-31=0

We add all the numbers together, and all the variables

-13x-26=0

We move all terms containing x to the left, all other terms to the right

-13x=26

x=26/-13

x=-2

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