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x2+1.8x+0.81=420.25
We move all terms to the left:
x2+1.8x+0.81-(420.25)=0
We add all the numbers together, and all the variables
x^2+1.8x-419.44=0
a = 1; b = 1.8; c = -419.44;
Δ = b2-4ac
Δ = 1.82-4·1·(-419.44)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.8)-41}{2*1}=\frac{-42.8}{2} =-21+0.8/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.8)+41}{2*1}=\frac{39.2}{2} =19+1/1.6666666666667 $
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