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-31-4=5-5(1+5x)
We move all terms to the left:
-31-4-(5-5(1+5x))=0
We add all the numbers together, and all the variables
-(5-5(5x+1))-31-4=0
We add all the numbers together, and all the variables
-(5-5(5x+1))-35=0
We calculate terms in parentheses: -(5-5(5x+1)), so:We get rid of parentheses
5-5(5x+1)
determiningTheFunctionDomain -5(5x+1)+5
We multiply parentheses
-25x-5+5
We add all the numbers together, and all the variables
-25x
Back to the equation:
-(-25x)
25x-35=0
We move all terms containing x to the left, all other terms to the right
25x=35
x=35/25
x=1+2/5
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