1/3(x-3)=1/2(x+6)

Solution for 1/3(x-3)=1/2(x+6) equation:

1/3(x-3)=1/2(x+6)

We move all terms to the left:

1/3(x-3)-(1/2(x+6))=0


Domain of the equation: 3(x-3)!=0

x∈R



Domain of the equation: 2(x+6))!=0

x∈R


We calculate fractions


(2xx/(3(x-3)*2(x+6)))+(-3xx/(3(x-3)*2(x+6)))=0


We calculate terms in parentheses: +(2xx/(3(x-3)*2(x+6))), so:

2xx/(3(x-3)*2(x+6))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)



We calculate terms in parentheses: +(-3xx/(3(x-3)*2(x+6))), so:

-3xx/(3(x-3)*2(x+6))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

2xx-3xx=0