-30+2n=1-3(n+2)

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Solution for -30+2n=1-3(n+2) equation: 



-30+2n=1-3(n+2)

We move all terms to the left:

-30+2n-(1-3(n+2))=0



We calculate terms in parentheses: -(1-3(n+2)), so:

1-3(n+2)

determiningTheFunctionDomain
-3(n+2)+1

We multiply parentheses

-3n-6+1

We add all the numbers together, and all the variables

-3n-5

Back to the equation:

-(-3n-5)



We get rid of parentheses

2n+3n+5-30=0

We add all the numbers together, and all the variables

5n-25=0

We move all terms containing n to the left, all other terms to the right

5n=25

n=25/5

n=5

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