4(k+2)=12+3k

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Solution for 4(k+2)=12+3k equation: 



4(k+2)=12+3k

We move all terms to the left:

4(k+2)-(12+3k)=0

We add all the numbers together, and all the variables

4(k+2)-(3k+12)=0

We multiply parentheses

4k-(3k+12)+8=0

We get rid of parentheses

4k-3k-12+8=0

We add all the numbers together, and all the variables

k-4=0

We move all terms containing k to the left, all other terms to the right

k=4

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