-3/8(-6-2)=1/2(2y-3)-1

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Solution for -3/8(-6-2)=1/2(2y-3)-1 equation: 



-3/8(-6-2)=1/2(2y-3)-1

We move all terms to the left:

-3/8(-6-2)-(1/2(2y-3)-1)=0



Domain of the equation: 2(2y-3)-1)!=0

y∈R



We add all the numbers together, and all the variables

-(1/2(2y-3)-1)-3/8(-8)=0

We calculate fractions


()/(4y-6)+(-6y2/(4y-6)=0



We calculate terms in parentheses: +(-6y2/(4y-6), so:

-6y2/(4y-6

We multiply all the terms by the denominator


-6y2

We add all the numbers together, and all the variables

-6y^2

Back to the equation:

+(-6y^2)



We get rid of parentheses

-6y^2+()/(4y-6)=0

We multiply all the terms by the denominator


-6y^2*(4y-6)+()=0

We add all the numbers together, and all the variables

-6y^2*(4y-6)=0

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