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-3/5h=9
We move all terms to the left:
-3/5h-(9)=0
Domain of the equation: 5h!=0We multiply all the terms by the denominator
h!=0/5
h!=0
h∈R
-9*5h-3=0
Wy multiply elements
-45h-3=0
We move all terms containing h to the left, all other terms to the right
-45h=3
h=3/-45
h=-1/15
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