2x*(x-3)-(2x+1)*(x+3)=4

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Solution for 2x*(x-3)-(2x+1)*(x+3)=4 equation: 



2x(x-3)-(2x+1)(x+3)=4

We move all terms to the left:

2x(x-3)-(2x+1)(x+3)-(4)=0

We multiply parentheses

2x^2-6x-(2x+1)(x+3)-4=0

We multiply parentheses ..

2x^2-(+2x^2+6x+x+3)-6x-4=0

We get rid of parentheses

2x^2-2x^2-6x-x-6x-3-4=0

We add all the numbers together, and all the variables

-13x-7=0

We move all terms containing x to the left, all other terms to the right

-13x=7

x=7/-13

x=-7/13

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