-3/5b+7+2/5b=1

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Solution for -3/5b+7+2/5b=1 equation: 



-3/5b+7+2/5b=1

We move all terms to the left:

-3/5b+7+2/5b-(1)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We add all the numbers together, and all the variables

-3/5b+2/5b+6=0

We multiply all the terms by the denominator


6*5b-3+2=0

We add all the numbers together, and all the variables

6*5b-1=0

Wy multiply elements

30b-1=0

We move all terms containing b to the left, all other terms to the right

30b=1

b=1/30

b=1/30

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