-3/5(20x-10)=2/7(7x+35)

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Solution for -3/5(20x-10)=2/7(7x+35) equation: 



-3/5(20x-10)=2/7(7x+35)

We move all terms to the left:

-3/5(20x-10)-(2/7(7x+35))=0



Domain of the equation: 5(20x-10)!=0

x∈R





Domain of the equation: 7(7x+35))!=0

x∈R



We calculate fractions


(-21x7/(5(20x-10)*7(7x+35)))+(-10x2/(5(20x-10)*7(7x+35)))=0



We calculate terms in parentheses: +(-21x7/(5(20x-10)*7(7x+35))), so:

-21x7/(5(20x-10)*7(7x+35))

We multiply all the terms by the denominator


-21x7

We add all the numbers together, and all the variables

-21x^7

We do not support expression: x^7

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