-3/4e-3/8e=-18

Solution for -3/4e-3/8e=-18 equation:

-3/4e-3/8e=-18

We move all terms to the left:

-3/4e-3/8e-(-18)=0


Domain of the equation: 4e!=0

e!=0/4

e!=0

e∈R



Domain of the equation: 8e!=0

e!=0/8

e!=0

e∈R


We add all the numbers together, and all the variables

-3/4e-3/8e+18=0

We calculate fractions


(-24e)/32e^2+(-12e)/32e^2+18=0

We multiply all the terms by the denominator


(-24e)+(-12e)+18*32e^2=0

Wy multiply elements

576e^2+(-24e)+(-12e)=0

We get rid of parentheses

576e^2-24e-12e=0

We add all the numbers together, and all the variables

576e^2-36e=0

a = 576; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·576·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*576}=\frac{0}{1152}
=0
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*576}=\frac{72}{1152}
=1/16
$