3/4(f-5)=f+20

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Solution for 3/4(f-5)=f+20 equation: 



3/4(f-5)=f+20

We move all terms to the left:

3/4(f-5)-(f+20)=0



Domain of the equation: 4(f-5)!=0

f∈R



We get rid of parentheses

3/4(f-5)-f-20=0

We multiply all the terms by the denominator


-f*4(f-5)-20*4(f-5)+3=0

Wy multiply elements

-4f^2(f-80f(f+3=0

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