-3/(x+2)=7/(x+5)

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Solution for -3/(x+2)=7/(x+5) equation: 



-3/(x+2)=7/(x+5)

We move all terms to the left:

-3/(x+2)-(7/(x+5))=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (x+5))!=0

x∈R



We calculate fractions


(-3x)/((x+2)*(x+5)))+(-(7*(x+2))/((x+2)*(x+5)))=0



We calculate terms in parentheses: -(7*(x+2))/((x+2)*(x+5))), so:

7*(x+2))/((x+2)*(x+5))

We multiply all the terms by the denominator


7*(x+2))

We multiply parentheses

7x+

We add all the numbers together, and all the variables

7x

Back to the equation:

-(7x)



We add all the numbers together, and all the variables

-7x+(-3x)/((x+2)*(x+5)))+(=0

We multiply all the terms by the denominator


-7x*((x+2)*(x+5)))+(+(-3x)=0

We get rid of parentheses

-7x*((x+2)*(x+5)))+(-3x=0

We add all the numbers together, and all the variables

-3x-7x*((x+2)*(x+5)))+(=0

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