8(z-4)=4(2z-8)

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Solution for 8(z-4)=4(2z-8) equation: 



8(z-4)=4(2z-8)

We move all terms to the left:

8(z-4)-(4(2z-8))=0

We multiply parentheses

8z-(4(2z-8))-32=0



We calculate terms in parentheses: -(4(2z-8)), so:

4(2z-8)

We multiply parentheses

8z-32

Back to the equation:

-(8z-32)



We get rid of parentheses

8z-8z+32-32=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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