-3-2(a+4)=-6(1-a)-5

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Solution for -3-2(a+4)=-6(1-a)-5 equation: 



-3-2(a+4)=-6(1-a)-5

We move all terms to the left:

-3-2(a+4)-(-6(1-a)-5)=0

We add all the numbers together, and all the variables

-2(a+4)-(-6(-1a+1)-5)-3=0

We multiply parentheses

-2a-(-6(-1a+1)-5)-8-3=0



We calculate terms in parentheses: -(-6(-1a+1)-5), so:

-6(-1a+1)-5

We multiply parentheses

6a-6-5

We add all the numbers together, and all the variables

6a-11

Back to the equation:

-(6a-11)



We add all the numbers together, and all the variables

-2a-(6a-11)-11=0

We get rid of parentheses

-2a-6a+11-11=0

We add all the numbers together, and all the variables

-8a=0

a=0/-8

a=0

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