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3(2x-4)=2(3x+2)
We move all terms to the left:
3(2x-4)-(2(3x+2))=0
We multiply parentheses
6x-(2(3x+2))-12=0
We calculate terms in parentheses: -(2(3x+2)), so:We get rid of parentheses
2(3x+2)
We multiply parentheses
6x+4
Back to the equation:
-(6x+4)
6x-6x-4-12=0
We add all the numbers together, and all the variables
-16!=0
There is no solution for this equation
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