-3+4(2x-3)=7(x-3)+5

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Solution for -3+4(2x-3)=7(x-3)+5 equation: 



-3+4(2x-3)=7(x-3)+5

We move all terms to the left:

-3+4(2x-3)-(7(x-3)+5)=0

We multiply parentheses

8x-(7(x-3)+5)-12-3=0



We calculate terms in parentheses: -(7(x-3)+5), so:

7(x-3)+5

We multiply parentheses

7x-21+5

We add all the numbers together, and all the variables

7x-16

Back to the equation:

-(7x-16)



We add all the numbers together, and all the variables

8x-(7x-16)-15=0

We get rid of parentheses

8x-7x+16-15=0

We add all the numbers together, and all the variables

x+1=0

We move all terms containing x to the left, all other terms to the right

x=-1

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