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2y=-28+5(2y+4)
We move all terms to the left:
2y-(-28+5(2y+4))=0
We calculate terms in parentheses: -(-28+5(2y+4)), so:We get rid of parentheses
-28+5(2y+4)
determiningTheFunctionDomain 5(2y+4)-28
We multiply parentheses
10y+20-28
We add all the numbers together, and all the variables
10y-8
Back to the equation:
-(10y-8)
2y-10y+8=0
We add all the numbers together, and all the variables
-8y+8=0
We move all terms containing y to the left, all other terms to the right
-8y=-8
y=-8/-8
y=1
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