-3(y-3)=2(3-y)-(y-3)

Solution for -3(y-3)=2(3-y)-(y-3) equation:

-3(y-3)=2(3-y)-(y-3)

We move all terms to the left:

-3(y-3)-(2(3-y)-(y-3))=0

We add all the numbers together, and all the variables

-3(y-3)-(2(-1y+3)-(y-3))=0

We multiply parentheses

-3y-(2(-1y+3)-(y-3))+9=0


We calculate terms in parentheses: -(2(-1y+3)-(y-3)), so:

2(-1y+3)-(y-3)

We multiply parentheses

-2y-(y-3)+6

We get rid of parentheses

-2y-y+3+6

We add all the numbers together, and all the variables

-3y+9

Back to the equation:

-(-3y+9)


We get rid of parentheses

-3y+3y-9+9=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0