4y+2(y-1)=-3(-2y+2)

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Solution for 4y+2(y-1)=-3(-2y+2) equation: 



4y+2(y-1)=-3(-2y+2)

We move all terms to the left:

4y+2(y-1)-(-3(-2y+2))=0

We multiply parentheses

4y+2y-(-3(-2y+2))-2=0



We calculate terms in parentheses: -(-3(-2y+2)), so:

-3(-2y+2)

We multiply parentheses

6y-6

Back to the equation:

-(6y-6)



We add all the numbers together, and all the variables

6y-(6y-6)-2=0

We get rid of parentheses

6y-6y+6-2=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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