-3(y-2y)+3=-4(5y-y)+6+18y

Solution for -3(y-2y)+3=-4(5y-y)+6+18y equation:

-3(y-2y)+3=-4(5y-y)+6+18y

We move all terms to the left:

-3(y-2y)+3-(-4(5y-y)+6+18y)=0

We add all the numbers together, and all the variables

-3(-1y)-(-4(+4y)+6+18y)+3=0

We multiply parentheses

3y-(-4(+4y)+6+18y)+3=0


We calculate terms in parentheses: -(-4(+4y)+6+18y), so:

-4(+4y)+6+18y

determiningTheFunctionDomain
-4(+4y)+18y+6

We add all the numbers together, and all the variables

18y-4(+4y)+6

We multiply parentheses

18y-16y+6

We add all the numbers together, and all the variables

2y+6

Back to the equation:

-(2y+6)


We get rid of parentheses

3y-2y-6+3=0

We add all the numbers together, and all the variables

y-3=0

We move all terms containing y to the left, all other terms to the right

y=3