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5(x-7)(3x+8)=0
We multiply parentheses ..
5(+3x^2+8x-21x-56)=0
We multiply parentheses
15x^2+40x-105x-280=0
We add all the numbers together, and all the variables
15x^2-65x-280=0
a = 15; b = -65; c = -280;
Δ = b2-4ac
Δ = -652-4·15·(-280)
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{21025}=145$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-145}{2*15}=\frac{-80}{30} =-2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+145}{2*15}=\frac{210}{30} =7 $
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