-3(y-1)=-7(6+2y)+6y

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Solution for -3(y-1)=-7(6+2y)+6y equation: 



-3(y-1)=-7(6+2y)+6y

We move all terms to the left:

-3(y-1)-(-7(6+2y)+6y)=0

We add all the numbers together, and all the variables

-3(y-1)-(-7(2y+6)+6y)=0

We multiply parentheses

-3y-(-7(2y+6)+6y)+3=0



We calculate terms in parentheses: -(-7(2y+6)+6y), so:

-7(2y+6)+6y

We add all the numbers together, and all the variables

6y-7(2y+6)

We multiply parentheses

6y-14y-42

We add all the numbers together, and all the variables

-8y-42

Back to the equation:

-(-8y-42)



We get rid of parentheses

-3y+8y+42+3=0

We add all the numbers together, and all the variables

5y+45=0

We move all terms containing y to the left, all other terms to the right

5y=-45

y=-45/5

y=-9

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