5(y+3)+9=(y-4)+7

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Solution for 5(y+3)+9=(y-4)+7 equation: 



5(y+3)+9=(y-4)+7

We move all terms to the left:

5(y+3)+9-((y-4)+7)=0

We multiply parentheses

5y-((y-4)+7)+15+9=0



We calculate terms in parentheses: -((y-4)+7), so:

(y-4)+7

We get rid of parentheses

y-4+7

We add all the numbers together, and all the variables

y+3

Back to the equation:

-(y+3)



We add all the numbers together, and all the variables

5y-(y+3)+24=0

We get rid of parentheses

5y-y-3+24=0

We add all the numbers together, and all the variables

4y+21=0

We move all terms containing y to the left, all other terms to the right

4y=-21

y=-21/4

y=-5+1/4

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