-3(y+3)=6y-18

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Solution for -3(y+3)=6y-18 equation: 



-3(y+3)=6y-18

We move all terms to the left:

-3(y+3)-(6y-18)=0

We multiply parentheses

-3y-(6y-18)-9=0

We get rid of parentheses

-3y-6y+18-9=0

We add all the numbers together, and all the variables

-9y+9=0

We move all terms containing y to the left, all other terms to the right

-9y=-9

y=-9/-9

y=1

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