(-x-5)(3x-2)=3(x-2)(1-x)

Solution for (-x-5)(3x-2)=3(x-2)(1-x) equation:

(-x-5)(3x-2)=3(x-2)(1-x)

We move all terms to the left:

(-x-5)(3x-2)-(3(x-2)(1-x))=0

We add all the numbers together, and all the variables

(-1x-5)(3x-2)-(3(x-2)(-1x+1))=0

We multiply parentheses ..

(-3x^2+2x-15x+10)-(3(x-2)(-1x+1))=0


We calculate terms in parentheses: -(3(x-2)(-1x+1)), so:

3(x-2)(-1x+1)

We multiply parentheses ..

3(-1x^2+x+2x-2)

We multiply parentheses

-3x^2+3x+6x-6

We add all the numbers together, and all the variables

-3x^2+9x-6

Back to the equation:

-(-3x^2+9x-6)


We get rid of parentheses

-3x^2+3x^2+2x-15x-9x+10+6=0

We add all the numbers together, and all the variables

-22x+16=0

We move all terms containing x to the left, all other terms to the right

-22x=-16

x=-16/-22

x=8/11