-3(y+1)=6y-9+3(3y+6)

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Solution for -3(y+1)=6y-9+3(3y+6) equation: 



-3(y+1)=6y-9+3(3y+6)

We move all terms to the left:

-3(y+1)-(6y-9+3(3y+6))=0

We multiply parentheses

-3y-(6y-9+3(3y+6))-3=0



We calculate terms in parentheses: -(6y-9+3(3y+6)), so:

6y-9+3(3y+6)

determiningTheFunctionDomain
6y+3(3y+6)-9

We multiply parentheses

6y+9y+18-9

We add all the numbers together, and all the variables

15y+9

Back to the equation:

-(15y+9)



We get rid of parentheses

-3y-15y-9-3=0

We add all the numbers together, and all the variables

-18y-12=0

We move all terms containing y to the left, all other terms to the right

-18y=12

y=12/-18

y=-2/3

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