2x2+4x+3=1,5

Solution for 2x2+4x+3=1,5 equation:

2x^2+4x+3=1.5

We move all terms to the left:

2x^2+4x+3-(1.5)=0

We add all the numbers together, and all the variables

2x^2+4x+1.5=0

a = 2; b = 4; c = +1.5;
Δ = b2-4ac
Δ = 42-4·2·1.5
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2}{2*2}=\frac{-6}{4}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2}{2*2}=\frac{-2}{4}
=-1/2
$