-3(x-4)+7=2(8-4x)-12

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Solution for -3(x-4)+7=2(8-4x)-12 equation: 



-3(x-4)+7=2(8-4x)-12

We move all terms to the left:

-3(x-4)+7-(2(8-4x)-12)=0

We add all the numbers together, and all the variables

-3(x-4)-(2(-4x+8)-12)+7=0

We multiply parentheses

-3x-(2(-4x+8)-12)+12+7=0



We calculate terms in parentheses: -(2(-4x+8)-12), so:

2(-4x+8)-12

We multiply parentheses

-8x+16-12

We add all the numbers together, and all the variables

-8x+4

Back to the equation:

-(-8x+4)



We add all the numbers together, and all the variables

-3x-(-8x+4)+19=0

We get rid of parentheses

-3x+8x-4+19=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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