3(y+2)-y=38

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Solution for 3(y+2)-y=38 equation: 



3(y+2)-y=38

We move all terms to the left:

3(y+2)-y-(38)=0

We add all the numbers together, and all the variables

-1y+3(y+2)-38=0

We multiply parentheses

-1y+3y+6-38=0

We add all the numbers together, and all the variables

2y-32=0

We move all terms containing y to the left, all other terms to the right

2y=32

y=32/2

y=16

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