-3(x-3)-16=2(x-8)+11

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Solution for -3(x-3)-16=2(x-8)+11 equation: 



-3(x-3)-16=2(x-8)+11

We move all terms to the left:

-3(x-3)-16-(2(x-8)+11)=0

We multiply parentheses

-3x-(2(x-8)+11)+9-16=0



We calculate terms in parentheses: -(2(x-8)+11), so:

2(x-8)+11

We multiply parentheses

2x-16+11

We add all the numbers together, and all the variables

2x-5

Back to the equation:

-(2x-5)



We add all the numbers together, and all the variables

-3x-(2x-5)-7=0

We get rid of parentheses

-3x-2x+5-7=0

We add all the numbers together, and all the variables

-5x-2=0

We move all terms containing x to the left, all other terms to the right

-5x=2

x=2/-5

x=-2/5

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